0=5[x-(2-x)]-9(x+1)

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Solution for 0=5[x-(2-x)]-9(x+1) equation:


Simplifying
0 = 5[x + -1(2 + -1x)] + -9(x + 1)
0 = 5[x + (2 * -1 + -1x * -1)] + -9(x + 1)
0 = 5[x + (-2 + 1x)] + -9(x + 1)

Reorder the terms:
0 = 5[-2 + x + 1x] + -9(x + 1)

Combine like terms: x + 1x = 2x
0 = 5[-2 + 2x] + -9(x + 1)
0 = [-2 * 5 + 2x * 5] + -9(x + 1)
0 = [-10 + 10x] + -9(x + 1)

Reorder the terms:
0 = -10 + 10x + -9(1 + x)
0 = -10 + 10x + (1 * -9 + x * -9)
0 = -10 + 10x + (-9 + -9x)

Reorder the terms:
0 = -10 + -9 + 10x + -9x

Combine like terms: -10 + -9 = -19
0 = -19 + 10x + -9x

Combine like terms: 10x + -9x = 1x
0 = -19 + 1x

Solving
0 = -19 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
0 + -1x = -19 + 1x + -1x
Remove the zero:
-1x = -19 + 1x + -1x

Combine like terms: 1x + -1x = 0
-1x = -19 + 0
-1x = -19

Divide each side by '-1'.
x = 19

Simplifying
x = 19

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